Whenever j and k are positive integers such that (√3)^j = 27^k

Whenever j and k are positive integers such that (√3)j = 27k, what is the value of j/k?

F. 1/6
G. 3/2
H. 3
J. 4
K. 6

Answer

The correct answer is E.

For b > 0, b ≠1, bx = by means x = y.

(√3)j = 27k

32/j = 33k

j/2 = 3k

j/k = 6